Hoseason Island
  Hoseason Island Location in Antarctica | |
| Geography | |
|---|---|
| Location | Palmer Archipelago, Antarctica |
| Coordinates | 63°44′S 61°41′W / 63.733°S 61.683°WCoordinates: 63°44′S 61°41′W / 63.733°S 61.683°W |
| Archipelago | Palmer Archipelago |
| Length | 11.112 km (6.9047 mi) |
| Width | 5.556 km (3.4523 mi) |
| Highest elevation | 495 m (1,624 ft) |
| Highest point | Stopford Peak |
| Administration | |
|
None | |
| Demographics | |
| Population | 19 |
| Additional information | |
| Administered under the Antarctic Treaty System | |
Hoseason Island is an island 11 kilometres (6 nmi) long and 6 kilometres (3 nmi) wide, lying 37 kilometres (20 nmi) west of Trinity Island in the Palmer Archipelago, Antarctica. This name, which has appeared on charts for over 100 years, commemorates James Hoseason, first mate on the Sprightly, an Enderby Brothers sealing ship which operated in these waters in 1824–25.[1]
See also
References
- ↑ "Hoseason Island". Geographic Names Information System. United States Geological Survey. Retrieved 2012-06-27.
This article incorporates public domain material from the United States Geological Survey document "Hoseason Island" (content from the Geographic Names Information System).
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