Republican City Township, Harlan County, Nebraska
| Republican City Township | |
|---|---|
| Township | |
 Location in Harlan County | |
| Coordinates: 40°02′31″N 099°13′58″W / 40.04194°N 99.23278°WCoordinates: 40°02′31″N 099°13′58″W / 40.04194°N 99.23278°W | |
| Country | United States |
| State | Nebraska |
| County | Harlan |
| Area | |
| • Total | 36.02 sq mi (93.3 km2) |
| • Land | 26.09 sq mi (67.57 km2) |
| • Water | 9.93 sq mi (25.72 km2) 27.57% |
| Elevation | 1,975 ft (602 m) |
| Population (2000) | |
| • Total | 129 |
| • Density | 4.9/sq mi (1.9/km2) |
| GNIS feature ID | 0838208 |
Republican City Township is one of sixteen townships in Harlan County, Nebraska, United States. The population was 129 at the 2000 census. A 2006 estimate placed the township's population at 117.[1] The village of Republican City is less than a mile north of the township.
See also
References
- ↑ "Subcounty population estimates: Nebraska 2000-2006" (CSV). United States Census Bureau, Population Division. 2007-06-28. Retrieved 2008-02-26.
External links
Municipalities and communities of Harlan County, Nebraska, United States | ||
|---|---|---|
| City |  | |
| Villages | ||
| Townships | ||
| Unincorporated communities | ||
| Footnotes | ‡This populated place also has portions in an adjacent county or counties | |
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