United States presidential election in Missouri, 1860

United States presidential election in Missouri, 1860

November 2, 1860

Nominee Stephen A. Douglas John Bell John C. Breckinridge Party Democratic Constitutional Union Southern Democratic Home state Illinois Tennessee Kentucky Running mate Herschel Vespasian Johnson Edward Everett Joseph Lane Electoral vote 9 0 0 Popular vote 58,801 58,372 31,362 Percentage 35.52 35.26 18.94   Nominee Abraham Lincoln Party Republican Home state Illinois Running mate Hannibal Hamlin Electoral vote 0 Popular vote 17,028 Percentage 10.28

President before election James Buchanan Democratic Elected President Abraham Lincoln Republican

This article describes the United States presidential election, 1860, in Missouri.

Voters chose nine representatives, or electors to the Electoral College, who voted for President and Vice President. Missouri voted for the Democratic candidate, Stephen A. Douglas.

Presidential Candidate	Running Mate	Party	Electoral Vote (EV)	Popular Vote (PV)
Stephen A. Douglas	Herschel Johnson	Democratic	9[1]	58,801	35.52%
John Bell	Edward Everett	Constitutional Union	0	58,372	35.26%
John Breckenridge	Joseph Lane	Southern Democrat	0	31,362	18.94%
Abraham Lincoln	Hannibal Hamlin	Republican	0	17,028	10.28%

Statewide winner in bold.

References

1. 1860 Presidential General Election Results - Missouri