United States presidential election in New Mexico, 1992

United States presidential election in New Mexico, 1992

November 3, 1992

Nominee Bill Clinton George H.W. Bush Ross Perot Party Democratic Republican Independent Home state Arkansas Texas Texas Running mate Al Gore Dan Quayle James Stockdale Electoral vote 5 0 0 Popular vote 261,617 212,824 91,895 Percentage 45.9% 37.3% 16.1%

County Results   Clinton—60-70%   Clinton—50-60%   Clinton—40-50%   Bush—40-50%   Bush—50-60%

President before election George H. W. Bush Republican Elected President Bill Clinton Democratic

The 1992 United States presidential election in New Mexico took place on November 3, 1992, as part of the 1992 United States presidential election. This was the 20th U.S. Presidential election that New Mexico participated in since 1912. New Mexico voters chose five electors to the Electoral College, who voted for President and Vice President.

New Mexico was won by Governor Bill Clinton (D-Arkansas) with 45.90% of the popular vote over incumbent President George H.W. Bush (R-Texas) with 37.34%. Businessman Ross Perot (I-Texas) finished in third with 16.12% of the popular vote.^[1] Clinton ultimately won the national vote, defeating incumbent President Bush.^[2]

Results

United States presidential election in New Mexico, 1992[1]
Party		Candidate	Votes	Percentage	Electoral votes
	Democratic	Bill Clinton	261,617	45.90%	5
	Republican	George H.W. Bush (incumbent)	212,824	37.34%	0
	Independent	Ross Perot	91,895	16.12%	0
	Libertarian	Andre Marrou	1,615	0.28%	0
	U.S. Taxpayers'	Howard Phillips	620	0.11%	0
	Natural Law	John Hagelin	562	0.10%	0
	New Alliance	Lenora Fulani	369	0.06%	0
	Socialist Workers	James Warren	183	0.03%	0
	Workers World	Gloria La Riva	181	0.03%	0
	Prohibition	Earl Dodge	120	0.02%	0
Totals			569,986	100.0%	5

References

1. "1992 Presidential General Election Results - New Mexico". U.S. Election Atlas. Retrieved 9 June 2012.
2. "1992 Presidential General Election Results". U.S. Election Atlas. Retrieved 9 June 2012.