Swiss federal election, 1899
This article is part of a series on the politics and government of Switzerland |
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Federal elections were held in Switzerland on 26 October 1899. The Free Democratic Party retained its majority in the National Council.[1]
Electoral system
The 147 members of the National Council were elected in 52 single- and multi-member constituencies using a three-round system. Candidates had to receive a majority in the first or second round to be elected; if it went to a third round, only a plurality was required. Voters could cast as many votes as there were seats in their constituency.[2] There was one seat for every 20,000 citizens, with seats allocated to cantons in proportion to their population.[2]
Results
Voter turnout was highest in Schaffhausen (where voting was compulsory) at 86.4% and lowest in Obwalden at 21.3%.
Party | Votes | % | Seats | +/– |
---|---|---|---|---|
Free Democratic Party | 183,216 | 49.7 | 84 | –2 |
Catholic People's Party | 76,845 | 20.8 | 32 | +2 |
Liberal Centre | 51,764 | 14.1 | 20 | –1 |
Social Democratic Party | 35,488 | 9.6 | 4 | +2 |
Democratic Group | 18,003 | 4.9 | 7 | –1 |
Others | 3,409 | 0.9 | 0 | 0 |
Invalid/blank votes | 33,015 | – | – | – |
Total | 401,750 | 100 | 147 | 0 |
Registered voters/turnout | 737,696 | 54.5 | – | – |
Source: Mackie & Rose,[3] BFS (seats) |
References
- ↑ Elections to the National Council 1848–1917: Distribution of seats by party or political orientation BFS
- 1 2 Dieter Nohlen & Philip Stöver (2010) Elections in Europe: A data handbook, p1886 ISBN 9783832956097
- ↑ Thomas T Mackie & Richard Rose (1991) The International Almanac of Electoral History, Macmillan
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